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Marble rolling toy solution.
Whenever a marble encounters a lever it causes the lever to reverse after the marble passes so the next marble will take the opposite.
Enjoy the course of rolling balls by combining blocks of various colors kumikumi slope of japanese company kumon.
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Whenever a marble encounters a lever it causes the lever to reverse after the marble passes so the next marble will take the opposite branch.
A marble is dropped at a or b.
And the ending is 1 and x mod 4 0 or x 3 mod 4 0 x is the numbers of 0 s and 1 s.
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There are three levers in this figure let s say x1 x2 and x3 from left to right.
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Levers x1 x2x1 x2 and x3x3 cause the marble to fall either to the left or to the right.
A marble is dropped at a or b.
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Whenever a marble encounters a lever it causes the lever to reverse after the marble passes so the next marble will take the opposite branch.
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A toy that rolls a ball.
A marble is dropped at aa or bb.
Whenever a marble encounters a lever it causes the lever to reverse before the marble passes so the next marble will take the opposite branch.
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Above figure represents a marble rolling toy.
Levers x 1 x 2 and x 3 cause the marble to fall either to the left or to the right.
In fig 2 8 is a marble rolling toy.
There are three levers in this figure let s say x1 x2 and x3 from left to right.
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Penultimate configuration interrupts is where means or.
For my question from this case i get the subcase.
A marble rolling toy in fig 2 8 is a marble rolling toy.
Above figure represents a marble rolling toy.
According that solution exist a case.
Model this toy by a finite automaton.
A marble is dropped at a or b.